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Topic: balancing reactions ...  (Read 2580 times)

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Offline or_il

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balancing reactions ...
« on: January 05, 2011, 10:47:20 AM »
Hello :)
How are you ?

Somebody can help me please to balance this reaction ?

H3O+  +  Cr2O7  ---> Cr  +  H2O


Thank you !

Offline Borek

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Re: balancing reactions ...
« Reply #1 on: January 05, 2011, 03:00:58 PM »
It can't be balanced the way you wrote it. You omitted charges, and they play an important role. Besides, this looks like a half reaction - that means it can't be balanced without adding electrons on one of the sides.
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Offline Twigg

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Re: balancing reactions ...
« Reply #2 on: January 05, 2011, 03:17:22 PM »
@Borek, True, but textbooks give these problems all the time expecting you to insert hydrogen ions and/or hydroxide ions where appropriate.

1) Split the half reactions
2) balance each individually with coefficients of e-
3) multiply both equations by terms that make the e- coefficients equal their lowest common multiple
4) re-combine equations

The rest isn't hard.

Offline chronictonic

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Re: balancing reactions ...
« Reply #3 on: January 06, 2011, 03:56:05 AM »
This is interesting too;

Chromium ions exist in a hexhydrate form denoted

[Cr.(H2O)6]^(3+)

these ions are acidic and in constant equilibrium between the states

[Cr.(H2O)6]^(3+)  AND  [CrOH.(H2O)5]^(2+) + H3O^(+)

I know its not relevant but i found it interesting

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