[vivekrai]

Sorry for posting this as many people are having problem with me here . Anyways, the question and my solution are here, Please tell me where am I wrong?

Q:  CsCl has BCC structure in which Cs atoms occupy Body Center and Cl the corner sites. If density is 3.99 g/cc , Calculate :
a) The length of edge of Unit Cell
b) The distance b/w Cs⁺ and Cl^- ions

We have, $$\rho =\frac{Z \cdot M}{a^3 \cdot N_A}$$

Putting values as Rho = 3.99 g/cc , M = 168.5 g (Z =1) , N_A the usual Avogadro Number, We get a = 412 pm ?

Is it correct?

[AWK]

http://www.ilpi.com/inorganic/structures/cscl/index.html