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Topic: Calculate solutions given acidity constant and a chemical equilibrium  (Read 3490 times)

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Offline Fzang

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The problem sounds more or less like this (translated)

"Oxalic acid H2C2O4 is a diprotic acid with the acidity constants K(1)=10-1.23 M and K(2)=10-4.19 M. The ionization constant of water is Kv=10-14.00 M2

Calculate the concentrations of C2O42-, HC2O4-, Na+ and OH- in a 0.01 M solution of Na2C2O4. Finally, calculate the pH of the solution. Only the equilibrium is taken into consideration.

C2O42- + H2O <--> HC2O4- + OH-"


Can someone help me get started?

Offline Borek

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Re: Calculate solutions given acidity constant and a chemical equilibrium
« Reply #1 on: January 17, 2011, 05:28:44 PM »
Calculate Kb, assume C2O42- is a weak base.
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Offline Fzang

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Re: Calculate solutions given acidity constant and a chemical equilibrium
« Reply #2 on: January 17, 2011, 05:40:40 PM »
Kb = Kw/K(2), so

Kb = 1.55 * 10-10

I'm sorry, still lost.  :-X

Offline rabolisk

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Re: Calculate solutions given acidity constant and a chemical equilibrium
« Reply #3 on: January 17, 2011, 10:26:17 PM »
How does Kb relate to the reaction you wrote? Your value is correct, but what does it mean?

Offline Vidya

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Re: Calculate solutions given acidity constant and a chemical equilibrium
« Reply #4 on: January 18, 2011, 01:59:58 AM »
Kb = Kw/K(2), so

Kb = 1.55 * 10-10

now you can set up ICE table

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