[natemorse5]

I've been working at this problem in every way I can think of, but I am not coming up with a correct answer.

A correct equation I calculated for the problem:  Pb(ClO3)2 + 2NaI = PbI2 + 2NaClO3

The part of the question I am having trouble solving is:  What mass of precipitate will form if 1.50L of the concentrated Pb(ClO3)2 is mixed with 0.650L of 0.190 NaI?  (Assuming the reaction goes into completion)

[rabolisk]

When I hear that a reaction goes into completion, the first thing that pops into my head is limiting reagent.

[natemorse5]

My gues is that the 0.650L of 0.190 NaI is the limiting reagent.  If that is the case, how does it apply here?

[AWK]

Now write down a balanced reaction