[mac227]

I combined 3 mL of a .5 M solution of CaCl₂ with  3 mL of a .5 M K₂CO₃ solution. 

I am trying to find out the number of moles of each starting material and the moles of product.

My equation is CaCl₂ + K₂CO₃  CaCl₂ (s) + 2K⁺ + 2Cl^-


 .5 K⁺ (.5mol / 1L) (1L / 1000mL) (3 mL / 1) (39 g K / 1 mol K ) (138.18 g K2CO3 / 1 mol) = .220727 g K⁺


(.5 mol Cl- / 1L ) (1L / 1000mL) ( 3mL / 1 mol) (35.45 g / 1 mol) = .053175 g / mL 

correct ?

[Borek]

CaCl₂ + K₂CO₃  CaCl₂ (s) + 2K⁺ + 2Cl^-

What happened to CO₃^2-?