[ch3mgirl]

Question: How many grams of magnesium metal must be heated in a nitrogen atmosphee to produce 10.01 grams of magnesium nitride?

I have the balanced equation as:
3Mg + N₂  Mg₃N₂

When I calculate moles of Mg₃N₂ I end up with 0.0992 mol.

And from there I calculated

0.0992 mol Mg₃N₂ * (3 mol Mg/1 mol Mg₃N₂) * (24.305g/1 mol Mg) = 6.723 g of Mg

Could someone please check me?

[rabolisk]

I got 7.230 grams.

[opti384]

Seems like you miscalculated here

0.0992 mol Mg3N2 * (3 mol Mg/1 mol Mg3N2) * (24.305g/1 mol Mg) = 6.723 g of Mg

[ch3mgirl]

Seems like you miscalculated here

0.0992 mol Mg3N2 * (3 mol Mg/1 mol Mg3N2) * (24.305g/1 mol Mg) = 6.723 g of Mg

Oh wow, not sure what I did there... okay, I got 7.233 g Mg. Thanks so much! I really need to check how I'm putting this stuff into a calculator.