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Partial Pressures: 2SO2(g) + O2(g) --> 2SO3(g)
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Topic: Partial Pressures: 2SO2(g) + O2(g) --> 2SO3(g) (Read 9788 times)
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alimarie
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Partial Pressures: 2SO2(g) + O2(g) --> 2SO3(g)
«
on:
September 09, 2005, 04:57:46 PM »
I need help on this problem. I have no idea how to solve it! Please reply A.S.A.P. it's due in a few hours.
Consider the reaction:
2SO2(g) + O2(g) --> 2SO3(g) at constant temperature. Initially a container is filled with pure SO3(g) at a pressure of 2 atm, after which equilibrium is allowed to be reached. If y is the partial pressure of O2 at equilibrium, the value of Kp is:
A.
(2 - 2y)2
-------
(y2)(2y)
B.
(2 - y)2
-------
(y2)(y/2)
C.
(2 - y)2
-------
(2y)2(y)
D.
(2 -2y)2
-------
(2y)2(y)
E. none of these
«
Last Edit: September 17, 2005, 02:31:06 AM by Mitch
»
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Borek
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Re:Partial Pressures *delete me*
«
Reply #1 on:
September 09, 2005, 06:29:28 PM »
First, write down expression for Kp.
Second, write down equilibrium amounts of all substances. You know what was initial pressure of SO
3
, all pressures can be calculated using something like ICE table.
Finally, substitute.
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ChemBuddy
chemical calculators - stoichiometry, pH, concentration, buffer preparation,
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alimarie
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Re:Partial Pressures *delete me*
«
Reply #2 on:
September 09, 2005, 07:02:48 PM »
I don't know what to se for Kp, can you guide me exactly what to do pleasE?
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Partial Pressures: 2SO2(g) + O2(g) --> 2SO3(g)