Hello,
Specifically about Grignards...I'm a little confused as to how you find the percent yield.
Reaction was as followed:
So I do know that my limiting reagent is the bromobenzene. I started with 10.4g and multiplied it by it's MW, giving me 0.06623 mols. However, I am confused because my TA mentioned something about having to find the molar ratio between each reaction - but isn't the molar mass just 1:1 between each step? So really, couldn't I just take 0.06623mol x (1mol benzoic acid/122.13g), giving me a theoretical yield of 8.08g? Then I do the whole percent yield bit.
And because it's 1:1, I can also figure out theoretically, how much of starting material, grignard reagent, and final product should have reacted/gotten. Actually, I'm thinking this is maybe what my TA meant...because I've only calculated the starting material and final product...but not actually how much grignard reagent could have/actually did react. But if this is the case, the thing that confuses me is the third compound...what exactly is it? Because I know that a bond between the O and MgBr sort of exists...but it's not a "true" ionic bond...
One more thing: What is the difference between gram atom and gram mole? It just mentioned it in the lab somewhere...and I can't seem to get a clear cut answer as to what it is.
Anyways, sorry this was so long and if it's a bit difficult to read...any comments/help would be greatly appreciated though.
Thank you!