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Topic: Question on ΔH  (Read 3083 times)

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Offline al526

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Question on ΔH
« on: March 08, 2011, 10:06:29 PM »
Consider the following reaction.
2 CH3OH(l) + 3 O2(g)  4 H2O(l) + 2 CO2(g)       ΔH = -1452.8 kJ
What is the value of ΔH if the equation is multiplied throughout by 2?

Would the ΔH stay the same? (I don't quite understand why though-could someone explain?)
Thanks!!!
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Offline opti384

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Re: Question on ΔH
« Reply #1 on: March 08, 2011, 10:43:31 PM »
The value of ΔH will be doubled.
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Offline vmelkon

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Re: Question on ΔH
« Reply #2 on: March 16, 2011, 11:25:39 AM »
Isn't that -1452.8 kJ/mol?
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