This is not a textbook question. I dissolved 0.34g copper sulfate pentahydrate and 1.61g calcium chloride (not sure of the hydrate formula, obtained it as road salt but it had been left out) in 10mL of water in a plastic test tube hoping to isolate (more or less) CuCl2 so I could determine it's color at a given concentration. I got some yellow/green solid trapped under the excess solids and white precipitate (CaSO4, I expect), and a milky blue solution. However, I also got a bunch of clear gas bubbling out. This was in a closed test tube, and the reaction was endothermic (I felt it got colder, initial temp was 24.5*C), so Henry's Law might explain it in terms of a decrease in the air pressure inside the test tube. That's the most elegant and convenient solution I can come up with. I also took the pH of the resulting solution with a piece of litmus paper. I don't really trust a litmus paper pH test, but it indicated a pH of 5. Also, when I mixed up the contents, the greenish solid settled beneath the blue, so I expect it had a density greater than copper sulfate.
To reduce the problem a bit, I can fill in as much as I know about the chemical reaction in pieces:
1. CuSO4_5H2O (s) <-> Cu2+ (aq) + SO42- (aq)
2. CaCl2_?H2O (s) -> Ca2+ (aq) + 2Cl- (aq)
3. Ca2+ (aq) + SO42- (aq) (<)-> CaSO4 (s)
4. Cu2+ (aq) + 2Cl- (aq) (<)-> CuCl2 (s)
5. (unknown reactants) (<)-> ? (gas)
To reduce it even further, here's the complete break-down:
Chemical Species and Total Amounts Before Reaction:
Ca2+ (aq), >7.33E(-3) mol
Cl- (aq), >1.47E(-2) mol
Cu2+ (aq), <1.38E(-3) mol
SO42-, <1.38E(-3) mol
H2O (l), ~0.555 mol
H+ (aq), 10-7 mol
OH- (aq), 10-11 mol
Any ideas? What gases can you hypothetically get from that?