[kodos]

Calculate the standard potential for the process MnO₂ / Mn⁺²

Eº (MnO₄^- / Mn⁺²) = 1.51 V
Eº (MnO₄^- / MnO₂) = 1.70 V

(All reactions occur at low pH)

ATTEMPT: Combine the equations

MnO₂ + 2 H₂O MnO₄^- + 4 H⁺ + 3 e^-
MnO₄^- + 8 H⁺ + 5 e^- Mn⁺² + 4 H₂O
^{---------------------------------------------------}
MnO₂ + 4 H⁺ + 2 e^- Mn⁺² + 2 H₂O

Is the species HMnO₄ involved in the process? If so, where does it appear?

[Borek]

Is the species HMnO₄ involved in the process?

Of the MnO₂/Mn²⁺ reduction? No.

[kodos]

Thanks. I must've got confused because of the low pH.