I am now getting into trouble in preparing allyl bromide from the corresponding allyl alcohol using NBS/PPh3 condition in CH2Cl2. The estimated b.p. of my bromide should be around 100 oC.
i.e. CH3CH2C(H)=C(H)CH2Br
How could I get rid of the excess PPh3 and O=PPh3, and purify my bromide without significant loss of it??? Or, what's the appropiate workup procedure?
Thx a lot!!!