Hi, my exam is coming up, and I'm doing some old exams.
I've reached a question where I don't know how to solve.
The teacher wants us to present a reasonable mechanism for the reaction below and describe the cyclization in terms of Baldwins Rules.
Additional information: "The reaction might proceed to the same product via an alternative route which involves rearrangement."
This is what I've done. After radical initiation, the radical can now chose to do the ring closing mechanism on the double bond. Via Baldwin's rules it should rather want to do it via 7-exo-trig than an 8-endo-trig. So why is the 8 membered ring formed over the 7? Am I missing a step?
What's the rearrangement reaction that the teacher is hinting about?