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Topic: Sn2 vs E2  (Read 4260 times)

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Offline ibenami

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Sn2 vs E2
« on: April 12, 2011, 07:29:44 AM »
I have a question:

If I have a primary alkyl halide which can theoretically undergo either E2 or SN2 reactions with -OH, generally SN2 will prevail because E2 prefers tertiary alkyl halides. however, if the E2 reaction creates a conjugated diene which adds to its stability, will it prefer the E2, or the SN2? or will both occur?

Cl-CH=CH-CH2-CH2-Cl   +  -OH   -->  ?

Offline Mandeep Deka

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Re: Sn2 vs E2
« Reply #1 on: April 12, 2011, 07:53:05 AM »
See, it all depends on the reaction conditions you use.
In your problem, E2 will prevail over SN2, because OH- is a very strong base, and the hydrogen atom which it will abstract to bring about the elimination is very acidic because of the presence of a double bond next to it. So in this problem the elimination product shall predominate even though both SN2 and E2 will occur simultaneously!!


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