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Topic: How does drinking NaNO3 and Cu2SO4 result in death?  (Read 3898 times)

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Offline cho_reunited

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How does drinking NaNO3 and Cu2SO4 result in death?
« on: April 19, 2011, 10:10:30 PM »
My equation is:
2CuNO3 (aq) + Na2SO4 (aq) === 2NaNO3 (aq) + Cu2SO4 (aq)

If a person drinks this solution they die.
Why is that?
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Offline Borek

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Re: How does drinking NaNO3 and Cu2SO4 result in death?
« Reply #1 on: April 20, 2011, 04:22:19 AM »
There is no reaction. One of the ions present is known for its toxicity.
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Offline AWK

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Re: How does drinking NaNO3 and Cu2SO4 result in death?
« Reply #2 on: April 20, 2011, 04:24:50 AM »
CuNO3 and Cu2SO4 only exist in texbook for training of chemical nomenclature
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Offline Borek

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Re: How does drinking NaNO3 and Cu2SO4 result in death?
« Reply #3 on: April 20, 2011, 11:07:21 AM »
Oops, missed Cu+.
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Offline xtremesci

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Re: How does drinking NaNO3 and Cu2SO4 result in death?
« Reply #4 on: April 22, 2011, 12:47:07 PM »
Rule of thumb when handling chemicals. All chemicals are poisonous.
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