A standard of Pb2+ for a gunshot residue analysis using ICP-OES is
prepared by first dissolving 1.0390 g dried Pb(NO3)2 in ultrapure water
containing 1% nitric acid. The solution is brought to volume in a class A 500
mL volumetric flask with an uncertainty of ± 0.20 mL. This solution is diluted
1/10 by taking 10 mL with an Eppendorf pipette, tolerance ± 1.3 µL) and
diluting this in 1% nitric acid to a final volume of 100 mL in a volumetric flask
with a tolerance of ± 0.08 mL. The balance used for weighing the Pb(NO3)2 has
an uncertainty of ± 0.0002 g. The atomic weights are as follows: Pb = 207.2; N
= 14.01; O = 16.00.
(i) Calculate the concentration of the final solution in mg L-1 of Pb2+
and report the answer with an appropriate number of digits
i've got the final answer of pb2+ to be 6499.631665mgL-1 exactly. i really don't understand the 'number of digits' part of the question. does it want the final answer to be 3 sig. fig?