Chemical Forums
1 Hour
1 Day
1 Week
1 Month
Forever
September 29, 2024, 02:14:39 PM
Forum Rules
: Read This Before Posting
Home
Help
Search
Login
Register
Chemical Forums
Chemistry Forums for Students
High School Chemistry Forum
Nuclear decay
« previous
next »
Print
Pages: [
1
]
Go Down
Topic: Nuclear decay (Read 2852 times)
0 Members and 1 Guest are viewing this topic.
hvard78
Regular Member
Posts: 10
Mole Snacks: +0/-0
Nuclear decay
«
on:
May 03, 2011, 04:51:33 PM »
If you have a 1000g sample of U-238, how much will be left after 2,500,000,000 years?
Do I do like 2.5 billion/2, then do 2^x=that number, then divide 1000 by x?
Logged
SirRoderick
Full Member
Posts: 101
Mole Snacks: +10/-1
Re: Nuclear decay
«
Reply #1 on:
May 03, 2011, 04:54:31 PM »
What is the half-life of U-238 and what does that figure mean?
Logged
hvard78
Regular Member
Posts: 10
Mole Snacks: +0/-0
Re: Nuclear decay
«
Reply #2 on:
May 03, 2011, 04:59:18 PM »
I just searched it up. It has a half life of 4.468 billion years
Logged
hvard78
Regular Member
Posts: 10
Mole Snacks: +0/-0
Re: Nuclear decay
«
Reply #3 on:
May 03, 2011, 05:02:15 PM »
WAITT
is it 555.6 g?
Logged
SirRoderick
Full Member
Posts: 101
Mole Snacks: +10/-1
Re: Nuclear decay
«
Reply #4 on:
May 03, 2011, 05:04:55 PM »
Well then, keeping that in mind.
N(t) = N
0
* e^{-lambda*t}
How could you use this formula, which should be familiar I think?
EDIT
Hang on I'll check
EDIT 2
I'm getting 675g on a rough pass. (didn't really pay attention to roundings and significant numbers)
«
Last Edit: May 03, 2011, 05:22:47 PM by SirRoderick
»
Logged
Print
Pages: [
1
]
Go Up
« previous
next »
Sponsored Links
Chemical Forums
Chemistry Forums for Students
High School Chemistry Forum
Nuclear decay