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Topic: Does delta H of isothermal expansion of an ideal gas =0 ?  (Read 12386 times)

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Offline skp524

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Does delta H of isothermal expansion of an ideal gas =0 ?
« on: May 06, 2011, 10:37:34 AM »
By1st law of thermodynamics :dU=dq+dw
Isothermal process: dU=0 , dT=0
By definition : H=U+PV=U+nRT (ideal gas, PV=nRT)

Therefore, dH= dU+ nRdT = 0 + 0 =0
Am i right?


Also, i want to ask whether delta G= -RT lnK  K refers to Kp or Kc?
« Last Edit: May 06, 2011, 11:19:14 AM by skp524 »

Offline tamim83

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Re: Does delta H of isothermal expansion of an ideal gas =0 ?
« Reply #1 on: May 06, 2011, 12:30:13 PM »
Quote
By1st law of thermodynamics :dU=dq+dw
Isothermal process: dU=0 , dT=0
By definition : H=U+PV=U+nRT (ideal gas, PV=nRT)

Therefore, dH= dU+ nRdT = 0 + 0 =0
Am i right?

Yes, you are. 


Quote
Also, i want to ask whether delta G= -RT lnK  K refers to Kp or Kc?

I believe it can be used for either. 

Offline Borek

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Re: Does delta H of isothermal expansion of an ideal gas =0 ?
« Reply #2 on: May 06, 2011, 04:39:15 PM »
Quote
Also, i want to ask whether delta G= -RT lnK  K refers to Kp or Kc?

I believe it can be used for either. 

When there are gases involved and there is a volume change, Kc doesn't equal Kp, so it won't work.
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Offline tamim83

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Re: Does delta H of isothermal expansion of an ideal gas =0 ?
« Reply #3 on: May 07, 2011, 10:47:11 PM »
Quote
When there are gases involved and there is a volume change, Kc doesn't equal Kp, so it won't work.

Hmm, so which constant does the delta G = -RTlnk equation refer to?  When I went back through my textbooks, it didn't say.  Does it just depend on the reaction?

Offline Borek

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Re: Does delta H of isothermal expansion of an ideal gas =0 ?
« Reply #4 on: May 08, 2011, 05:47:56 AM »
To be honest I don't know. My bet is that Kp is the correct one, and Kc is only an approximation. Note that when dealing with equilibrium where both gas and solutes are present we mix both concentrations and pressures in reaction quotient. However, as we deal mostly with solutions we are using Kc and treat it as a correct one, when it is only an approximation. But I can be wrong.
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Offline Jorriss

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Re: Does delta H of isothermal expansion of an ideal gas =0 ?
« Reply #5 on: May 08, 2011, 12:33:15 PM »
From my textbook, it's formally derived for Kp standard and from there, it's just used whenever necessary in any form, which, is odd come to think of it. For sure, it's for Kp standard, I've seen the derivation. But we also use it for solubility products, hetergeneous equilibrium constants, etc.

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