[starsnhearts89]

These are the last problems i've been struggling with and I wanted to do them as well as understand how to do them. Any help would be appreciated  

Potassium hydrogen phthalate (has a molar mass = 204.22 g/mole) is a weak acid with one acidic hydrogen. It's usually used to standardize NaOH(aq) solutions. During the titration 14.265 mL of NaOH was needed to react with 0.2053 g of potassium hydrogen phthalate. What was the molarity of the NaOH solution that was added? The reaction follows 1:1 stoichiometry.

and

If Vinegar is actually 5.0% by mass acetic acid in water, what is your percent error?
Percent error = (│actual value – your experimental value│/ actual value) x 100

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For the first one I divided the 0.2053 g of KHP with the molar mass of KHP getting me .0010053 . Then I divided that by 14.265 mL NaOH. That got me 7.047 x 10^-5 M (im very unsure of this though!)

[Dan]

For the first one I divided the 0.2053 g of KHP with the molar mass of KHP getting me .0010053 . Then I divided that by 14.265 mL NaOH. That got me 7.047 x 10^-5 M (im very unsure of this though!)

Watch your units. Remember that M = mol/L. By dividing mol by mL you have determined the concentration of NaOH in mol/mL.