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Topic: Reduction of nitrobenzene  (Read 2792 times)

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Offline arani.b

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Reduction of nitrobenzene
« on: June 11, 2011, 01:51:20 AM »
Recently I encountered a problem which reads,

Ph-NO2 + LiAlH4  :rarrow: PhN=NPh (azobenzene)  but,

Ph-NO2 + NaBH4/Pd-C  :rarrow: Ph-NH2 (aniline)

Explain.


Now I know that nitrobenzene on reduction in acidic media gives aniline and on reduction in alkaline media gives azobenzene. But I can't understand how is it applicable in the above case. Please help.

Offline nox

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Re: Reduction of nitrobenzene
« Reply #1 on: June 12, 2011, 12:29:56 AM »
I presume that H2 generated from decomposition of NaBH4 is the actual reductant in the second example.

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