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Topic: Lead sulphate and nitric acid  (Read 15710 times)

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guantou

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Lead sulphate and nitric acid
« on: September 26, 2005, 07:31:47 AM »
Can anyone please tell me the result when lead sulphate is put into nitric acid? (both in aqueous form)

and does anything happens when H2O is added into sulphuric acid?

thanks
« Last Edit: September 26, 2005, 07:32:47 AM by guantou »

Tobes

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Re:Lead sulphate and nitric acid
« Reply #1 on: September 26, 2005, 11:05:15 PM »
well it depends on what charge Pb has. It could have a 2+ or 4+ charge.
To solve these problems you need the formula of the compound, and find the charges for them. Then you write out the equation and balance the charges for both sides. Then you balance the equation by making the elements on each side equal.

If it has a 2+ charge then PbSO4(aq)+2HNO3(aq)----> Pb(NO3)2(aq)+H2SO4(aq)
You could figure it out if the Pb is 4+ charge.
But i can't help you on the H2O + H2SO4.... but i know its a strong acid which means it ionizes 100% if that helps.

Offline AWK

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Re:Lead sulphate and nitric acid
« Reply #2 on: September 27, 2005, 03:43:27 AM »
1. concerning PbSO4 - it is insoluble(poorly soluble)  in water and diluted acids.
Hot concentrated HNO3 dissolves PbSO4moderately  because of equilibrium reaction
2PbSO4 + 2HNO3 = Pb(HSO4)2 + Pb(NO3)2

Surprisingly - acetates, eg ammonium acetate dissolve PbSO4 easily
PbSO4 + 4CH3COONH4 = [Pb(CH3COO)4 ]2- + SO42- + 4NH4+
« Last Edit: September 27, 2005, 07:16:18 AM by AWK »
AWK

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