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Topic: difference between oxidation number method and half-reaction method for redox  (Read 5789 times)

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Offline rleung

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Hi,

I am confused about when to use the half-reaction method or oxidation number method for balancing equations.  I always thought they were interchangeable, but they do not appear to always be.  For example, here is an equation I cannot seem to balance via both methods:

Cu(s) + HNO3(aq) ---> Cu(NO3)2 (aq) 2NO2(g) + H2O(l)

I cannot seem to balance this via the half-reaction method.  I split up the equations into the following:

Cu(s) ---> Cu(2+) + 2e-

2e- + 6HNO3 ---> 4NO3(-) + 2NO2 + 2H2O + 2H(+)
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Cu(s) + 6HNO3(-) ---> Cu(2+) + 4NO3(-) + 2NO2 + 2H2O + 2H(+)

However, if I balance it via the oxidation number method, I get the following:

Cu(s) + 4HNO3 (aq) ---> Cu(NO3)2(aq) + 2NO2(g) + 2H2O(l)

Am I doing something wrong?  Thanks.

Ryan
« Last Edit: September 29, 2005, 10:34:21 PM by rleung »

Offline mike

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They are the same you just haven't cancelled everything out in the first one.

2 H+ and 4 NO3- is the same as 2 HNO3 and 2 H+

you can then get rid of 2 HNO3 from both sides of the equation.
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Offline Borek

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Adding to mike's comment: also note that one equation is "normal" while other is ionic (not yet "net" ionic ;) ) - that makes it more difficult for you to spot that they are the same.
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