Well, IMHO the data given in the problem aren't correct. So, assuming the final NO
2 pressure is mistaken, the solution is pretty simple:
2 NO
2(g) 2NO
(g) + O
2(g)P
i (atm) 0,42 0 0
P
f (atm) 0,42 - 2P 2P P
So, substituting in the K
p formula:
K
p =
P2NO PO2 /
P2NO2 =
4P3 /
(0,42 - 2P)2.
Solving the 3
rd degree equation resulting, you get the following results:
P
1 = 157 atm.
P
2 = 0,202 atm.
P
3 = 0,218 atm.
As it is pointed out by substitution in K
p, the latter is the correct one.