I think i got these titration-calculations down but just to sure I did this correctly
For this experiment I preformed a rebox titation with potassium dichromate to analyze iron oxide samples
so first i prepared the potassium dichromate solution and calculated the molarity of the solution:
2.49g k2CrO7 X (1mole/294.185g KsCr2O7)=.008464 mole K2Cr2O7
molarity .008464 mole K2Cr2O7/0.500L=.016928 or .017M
Then for the first trial
.4227g of Fe2O3
43.50 mL of K2Cr2O7
according to the equation its a 6:1 ratio
.04350 L X .017M=7.395X10^-4 moles of K2Cr2O7
7.395X10^-4 X 6 =.004437 moles of Fe
.004437 mol of Fe X 55.847g/mol=.247793 g
.247793 g / .4227g X 100=58.6% Fe in the iron ore sample
are these calculations correct I have a feeling I am forgetting something.
thanks in advanced