In a loop-the-loop ride a car goes around a vertical, circular loop at a constant speed. The car has a mass m = 252 kg and moves with speed v = 14.64 m/s. The loop-the-loop has a radius of R = 9.1 m.
1)What is the magnitude of the normal force on the car when it is at the bottom of the circle? (But as the car is accelerating upward.)
W=m(g)=N. So 252kg(9.81)=2472.12