If 25.0 mL of a 0.750 M Pb(ClO3)2 solution and 150.0 mL of a 0.125 M Na2SO4 solution were used in the reaction, then what was the concentration of sodium ions in solution AFTER the reaction?
Here's all I can do:
Pb(ClO3)2 + Na2SO4 --> PbSO4 + (ClO3)2 Na2
I'm really confused and stressed. I really appreciate your help. Thank you very much in advance.