In this reaction the amount of NaOH and the way it is added determine the final product. compound II is likely to be the product of this reaction ,employment of a stronger base or modification of the reaction conditions could produce III. deprotonation of II requires vigorous conditions as intramolecular hydrogen bonding and field effect would make deprotonation unfavorable.It must be noted that intramolecular hydrogen bonding in II is more effective than I.