Hi guys,
I have a questionmark in my mind about a question:
2Na
3PO
4 (aq) + 3Mg(NO
3)
2 (aq)
Mg
3(PO
4)
2 (s) + 6NaNO
3 (aq)
The amounts getting in the reaction are 0.1 mol and 0.1mol.
It is not the answer, but one of the answers related with this question is:
"Since nitrate ion is a spectator ion, the concentration of nitrate ion in the final solution will be the same as in the original magnesium nitrate solution."
This is true to me. The NO
3 ion is a spectator in the aqueous solution and it gets out, 0.1mol, as it gets in, 0.1mol. Because its not actually getting in the reaction.
What do you think? I am distressed for I will take the test Saturday.. I cant see anything anymore.. where am I wrong? If you give me a clue, it will be relieving.. thank you guys..