[gorlax]

Hi, I have this lab coming up and have to write out the procedure prior to class. I have a basic idea on what needs to be done but would like to double check my idea.

Given: .070g of a solid mixture containing 98% neutral organic compound and 2% NaCl
Chemicals: H20, dichloromethane, sodium Sulfate, TLC reference, TLC solvent.
Goal1: use extraction to isolate the organic solid from the inorganic salt. Determine Percent Recovery
Goal2: determine the products possible identity by taking  a TLC of both the isolate product and reference mixture.

Ok so goal 1 wants the ".070g of solid mixture" to be separated from the "inorganic salt NaCl"
1. Mix dichloromethane and Given substances together. The neutral organic compound should move into the organic layer "dichloromethane". While the salt remains in the aqueous phase. Then using sep funnel drain out aqueous layer into beaker, set aside. Then take organic layer and pour off into new beaker. add sodium sulfate to dehydrate the layer. Filter off sodium sulfate, evaporate solvent. Scrape yield, Weigh, Calculate percent recovery.

Create TLC! I know this really well so I don't think I need to go over this procedure.

I hope I have this right. I am a little confused on whether the NaCl stays in the Water, but according to what i have hypothesized about the procedure it has to for this to work. I know that NaCl is much more soluble in water then Ch2cl2 but not sure if it will contaminate my yield which is my Grade! any corrections,comments, or added advice is needed! Thanks

[Doc Oc]

That looks good to me, although you left out the part about adding water to the reaction (although you do correctly say that you need to partition the compounds between organic/aqueous phases, so I gather you knew what you were talking about).

[helenn]

From the way you've written the separation it looks like you think the bottom layer is the aqueous layer, but I just wanted to make sure you know the dichloromethane is heavier than water and will be the bottom layer in your sep funnel.