I did an assignment in class where we were given a table with temperature and the rate constant at that temperature. Using the graph of the information, we found activation energy for
2 HI(g) -> I(2) (gas) + H2 (gas)
My teacher wanted activation energy per mole of HI(g) so he told us to double the activation energy we found with the slope of the graph. Why do we double the activation energy, if HI is at 2 moles in the chemical equation and we want the activation energy per mole? Shouldn't the EA be less if less of the reactant is there to absorb the energy?