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Topic: Reduction of Vanillin  (Read 2036 times)

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Offline Amndz

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Reduction of Vanillin
« on: October 23, 2011, 09:43:29 PM »
Why is less borohydride needed to complete the reaction if 1M NaOH/H2O is used as the solvent rather than MeOH?

Is it because NaOH is more basic and it dissociates easily in water? That's about all that I can think of..

Thanks in advance!
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Offline Honclbrif

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Re: Reduction of Vanillin
« Reply #1 on: October 24, 2011, 08:54:59 AM »
Think about the reactivity of borohydride. Why might it behave better under basic conditions rather than neutral or acidic conditions?
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