[eddzzz]

Hey guys. Hope you can help me out on this one. so heres the question:

At an altitude of 50km the average atmospheric temperature is 0^oC. What is the average number of air molecules per cubic centimeter at this altitude.

This is how fare I have got:

M = 28.97 g mol^-1
g = 9.81 ms^-2
R = 8.314 J K^-1 mol^-1
Ph = pressure at any given height
P0 = pressure at sea level

Ph = P0e^-Mgh/RT

p @ 50km = 75.944Pa

          75.944 x 1 x 10^-2
Ph =  -------------------
           8.314 x 273

    =  3.346 x 10^-4

Is this correct? Thanks a lot.

Ed

[Alberto_Kravina]

          75.944 x 1 x 10^-2
Ph =  -------------------
           8.314 x 273

Beware: one cubic centimetre is not 10^-2 cubic metres. And, if we talk about molecules, you have to use Boltzmann constant instead of R

so

N / V = p(h) / ( k * T )

Use the correct units and volume and you'll have your result

My 600'th post

[eddzzz]

Ok. Thanks. So 1 cubic centimetre = 1 x 10^-6 cubic meters

so Ph = 75.444 * 50,000 * 1 * 10^-6
           -----------------------------
                (1.38 * 10^-23 * 273)

        = 1.001 * 10^21 moles per cubic centimeter. Is this correct?

[Borek]

1.001 * 10^21 moles per cubic centimeter. Is this correct?

No, it can't be correct. At STP one mole has a volume of 22.4 L, 10²¹ moles in 1 cm³ would be way denser than neutron stars.

No Idea why Alberto called for Boltzmann constant. I think you were on the right track.

[eddzzz]

I was thinking that myself. Nowhere I look does it mention the Boltzman constant?? So the answer I receive when I use R is * 10^-3. Can someone please confirm this. Thanks

[Alberto_Kravina]

No Idea why Alberto called for Boltzmann constant. I think you were on the right track.

I missed being corrected by you the last 4 years  

p*V = n * R * T (n = number of moles)

p*V= N * k * T (N=number of molecules)

Since the initial question is to get the number of molecules if you use the second equation you don`t have to divide the final result with Avogadro`s number.
The very first equation you posted is correct, you`ll get the number of moles if you put in the right conversion factor for the conversion of volume, but then do not forget to divide by avogadros number to get how many molecules there are+

Sorry if I caused any confusion, both paths lead to exactly the same result, though  

[eddzzz]

Ok so:

Ph = P0e^-Mgh/RT

p @ 50km = 75.944Pa

          75.944 x 1 x 10^-6
Ph =  -------------------
           8.314 x 273

    =  3.346 * 10^-8. And then I need to divide this by 6.022 * 10^23

    =  5.556 * 10^-32. Is this correct?