Hello everybody.
I have a really easy general question about Tris-HCl buffers. I found the outcome odd, but its probably a stupidity from my side
Today one of my collegues should prepare a Tris HCl buffer by first taking around 11 kg of Tris and dissolve it in around 30 kg of water. The pH should then be adjusted to pH 3.4 or something similar. It should be done with 10 kg HCl 10 % approximatly.
After 5 kg 10 % HCl the pH fell quickly down to 3 or similar. I know for buffers I have to use the Henderson Hasselbalch equation, but viewing this from a normal neutralization reaction I cant see how an amount this small could neutralize 11 kg Tris.
11 kg tris is 90 moles (11.000 g/ 121 g/mol = 91 moles)
91 moles of HCl: 91 moles x 35 g/mol = 3185 g
10 % HCl = 100 g/l
3185 g /100 g/l = 31 l
In this assumption the pH should first drop after the titration point and would then fall quickly.
Am I totally viewing this wrong? Know there is a bit roundoffs as this is a quick calculation.
Thanks in advance.