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Topic: kinetic energy? (E = 0.5*m*v^2)  (Read 5688 times)

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Offline tjalfe89

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kinetic energy? (E = 0.5*m*v^2)
« on: November 12, 2011, 10:44:24 AM »
hello. Why is the Kinetic enegy not directly proportional with the velocity, but with v^2? If u fx multiply the velocity with 3 the kinetic enegy will be 4.5 times bigger. Why is that? :-)

Offline LackOfFuel

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Re: kinetic energy? (E = 0.5*m*v^2)
« Reply #1 on: November 12, 2011, 01:23:55 PM »
What is the unit for energy? Joule?

Offline Borek

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Re: kinetic energy? (E = 0.5*m*v^2)
« Reply #2 on: November 13, 2011, 05:49:33 AM »
hello. Why is the Kinetic enegy not directly proportional with the velocity, but with v^2?

Because that's the way it is? It can be confirmed experimentally, it makes units consistent, what more do you need?
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Offline Jorriss

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Re: kinetic energy? (E = 0.5*m*v^2)
« Reply #3 on: November 14, 2011, 04:04:46 PM »
Work-Energy theorem may satisfy you, check it out.

http://en.wikipedia.org/wiki/Work_(physics)#Work_and_kinetic_energy

Offline juanrga

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Re: kinetic energy? (E = 0.5*m*v^2)
« Reply #4 on: November 16, 2011, 03:35:20 PM »
Think also that velocity is a vector but Energy a scalar.
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