4 HBr(g) + O
2(g)
2 Br
2(g) + 2 H
2O(g) K
c=88.5 at 500°C
The value of K
p for the above reaction is:
A) 13.9 B) 21.6 C) 885 D)5.62*10
4Correct me if I am wrong, but isn't the equation for this: K
p=K
c(RT)
:delta: n?
So shouldn't it be K
p=(88.5)(0.0821L*atm/mol*K*88.5K)
-1=12.2? Why is it not any of the answer choices?