[Swanie]

Hi. I got this question:
Consider a burner with a circular slot. Initially the air, the dilutant (N2) and the three fuels (H2, CH4 , C3H8) are at 300 K and 1 atm. All three different fluids (fuel+air+dilutant) at the nozzle are 55% by mass in N2.

I'd like help with 2 items:
1. When it states that the fluids are 55% by mass in N2, does the N2 include that which is included in the air?
2. How on earth does one get the N2 to be 55% by mass? Expecially as it is the heaviest of the elements?

Any help at all would be very much appreciated.
Regards,
Patrick

[Borek]

When it states that the fluids are 55% by mass in N2, does the N2 include that which is included in the air?

That would be my understanding.

How on earth does one get the N2 to be 55% by mass? Expecially as it is the heaviest of the elements?

I don't see why it should be a problem. Isn't it just a matter of choosing correct ratio of gases?