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Topic: Titration (pKb)  (Read 6120 times)

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Offline titration

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Titration (pKb)
« on: January 17, 2012, 01:08:48 PM »
Hello hope you can help me because this is quite embarrassing. My younger brother presented me with a problem he have to turn in soon about titration. He have to calculate pKb. I told him to go to the graph (image below) and determine pKa, which would be the titration midpoint (i.e. around 6 right?). It says in the exercise that it is at 25 degrees celsius so pKa+pKb=14 => pKb=8. Is that correct? Hope you can help me :)

« Last Edit: January 17, 2012, 01:34:34 PM by titration »

Offline Borek

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Re: Titration (pKb)
« Reply #1 on: January 17, 2012, 02:20:40 PM »
Midpoint is not the end point. Otherwise you are on the right track.
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Offline titration

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Re: Titration (pKb)
« Reply #2 on: January 17, 2012, 02:32:34 PM »
I'm not sure I follow, english isn't my first language so you might have to spell it out for me. But you are saying that pKa isn't equal 6 but actually lower?

Offline titration

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Re: Titration (pKb)
« Reply #3 on: January 17, 2012, 03:55:14 PM »
Ohh I think I get it now. Is it the midt point of the "second steep point"? at pH ~4,5? If it is correct would you mind explaining why it is so?

Offline Borek

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Re: Titration (pKb)
« Reply #4 on: January 17, 2012, 04:41:37 PM »
Midpoint is when the substance (acid or base) is titrated exactly in half. Steep part of the titration curve - called inflection point - is where the end point is. So you have to check the final volume from the inflection point, and then find the midpoint at half the volume.
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Offline titration

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Re: Titration (pKb)
« Reply #5 on: January 17, 2012, 04:58:47 PM »
So I take the volume at the titration midpoint ~20,5mL. Then I go to 10,25 mL and say that the pKa~9?

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Re: Titration (pKb)
« Reply #6 on: January 17, 2012, 06:37:20 PM »
Yes.
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Re: Titration (pKb)
« Reply #7 on: January 18, 2012, 12:11:20 AM »
Thank you very much :)

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