[missUK11]

In the attachment there is a reaction but i have worked out two products for it and i dont know which one is correct...can someone help me please?
 ( you may need to scroll to the right a bit to see my products properly below)
Many thanks

[Doc Oc]

In the absence of more information, I think your decision to put both products is reasonable.  If your professor has made any other claims (ie; hard vs soft nucleophiles) you'll need to take those into account.  Otherwise, I'm not aware of those reaction conditions favoring either carbonyl or conjugate reduction.

[discodermolide]

I think the cyanohydrin will be the major product, the other will certainly form as well but to a minor extent. There is a third possibility as well, in that the CN adds in a conjugate manor followed by attack of CN to give the cyanohydrin.
In all 3 possible products!

[orgopete]

I think it is going to be a conjugate addition reaction. Here is why. Aromatic aldehydes and ketones are generally less reactive than aliphatic for addition reactions. The methoxy is probably a slight electron withdrawing group, so it will help rather than hinder.

The other part is the conditions, 100°C in DMSO. I am concerned no protic source is listed. I don't think a cyanohydrin will be stable as the potassium alkoxide. The dimethylalkyl group will decrease reactivity at the beta carbon, so I could understand it being reluctant to add. I think that once added, it will be stable. So I am guessing these are conditions to form a thermodynamic product. I think 1,2-addition is more likely to be a kinetic product.

[me-go]

the following nucleophiles have 1,4 addition:

H₂O,ROH,NH₂R,Rcoo^-,CN^-,RS^-

so the right product is orginal product but it can be considered the left product because of high temprature and hard conditioning as a secondary product trace.

http://myup.ir/images/59001662763988116022.jpg

[missUK11]

Thankss soo much everyone, im gonna choose the product on the "right"