Calculate the E
o' for the half cell PtlNADH,NAD
+,H
+ at pH7 given that the Eo= -0.358V at 298k
NAD
+ +2e
- + H
+ NADH
I really dont know what equation i have to use for this question....is it a normal electrode potential question where i subtract the left cell E value from the right cell or is there another equation that i need to use please helpppp someone!!!