I've read and found that the solubility of chlorine in water is 3.26g/L
I tried to use this value to calculate the pH of a saturated solution of chlorine water.
Here's what i did:
Cl2+H2O<--->HClO+HCl
chlorine dissolves according to the above reaction until the solution reaches maximum solubility at 3.26g/L
then calculating the molarity, i did 3.26/71, ie mass concentration/Molar mass of Cl2 which gave~0.0459M
since the saturated solution is almost an equimolar mixture of HCl &HClO, from the reaction 0.0459M of Cl2 will give 0.0459M of HCl, giving 0.0459M of H+
then considering the HClO,
HClO<---->H+ + ClO-
k=[H+][ClO-]/[HClO]
k~3*10^-8
solving for [H+] gives [H+]~ 3.71*10^-5
solving for the pH, i'm getting about 1.34. I feel this value is too low. Is there something i'm missing? Pls i need clarification