[equos]

A solution is prepared by dissolving 23.7 g of CaCl2 in 375 g of water. The density of the resulting solution is 1.05 g/mL. Calculate the molarity of Cl- in the solution described above.

TY for helping

[Arkcon]

Great.  Now, to begin to solve this problem for yourself ... can you give us the formula for calculation molarity?  Do you see what data you have, and how you can use it to fill in the terms, and solve this problem.

[equos]

Great.  Now, to begin to solve this problem for yourself ... can you give us the formula for calculation molarity?  Do you see what data you have, and how you can use it to fill in the terms, and solve this problem.

Well..Ive actually tried, but never succeded I must add...

This is what ive done..

23.7/110 g/mol = mol CaCl2 X 2 to get Cl ions..

Then I divided mol Cl ion by 375+23.7/1.05 g/mol to find Molarity...

But the answer I get does not match with the options I got available on the test im taking?

[AWK]

375+23.7/1.05

This gives you volume in ml (cm³). You need volume in liters (dm³)