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Topic: balacing equations:Cr(NCS)64 - + Ce4+ ? Cr3+ + Ce3+ + NO3 - + CO2  (Read 6321 times)

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takjake

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balacing equations:Cr(NCS)64 - + Ce4+ ? Cr3+ + Ce3+ + NO3 - + CO2
« on: November 22, 2005, 01:33:03 PM »
Cr(NCS)64 - + Ce4+ ? Cr3+ + Ce3+ + NO3 - + CO2

Can anyone help me balance this equation.  How would I do it?  It seems to hard to do via the half-reaction method.  Also don't know how to apply oxidation number method to it.  Thanks.
« Last Edit: November 22, 2005, 01:56:29 PM by Mitch »
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Offline Albert

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Re:balacing equations:Cr(NCS)64 - + Ce4+ ? Cr3+ + Ce3+ + NO3 - + CO2
« Reply #1 on: November 22, 2005, 02:19:44 PM »
There's something missing in your equation: what happened to sulfur? And where does this oxygen come from?
Complete the reaction and, then, you will find balancing it easier.
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Offline Borek

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Re:balacing equations:Cr(NCS)64 - + Ce4+ ? Cr3+ + Ce3+ + NO3 - + CO2
« Reply #2 on: November 22, 2005, 02:48:54 PM »
Assuming reaction takes place in acidic solution and sulfur is oxidised to SO42- highest coefficient in the reaction equation will be 108 :)
« Last Edit: November 22, 2005, 02:53:48 PM by Borek »
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