Thanks djt;
I have checked my counting: there are 12 carbon environments and 13 peaks in the C-NMR, but I assume the one on the far right is solvent. The H-NMR has 8 peaks and 7 H-environments, so I think there's a sovent peak to the far right.
I've haven't run these myself (I'm at the stage where we just do IRs...), but have been given PDF files of H-NMR, C-NMR, HMBC and HMQC.
The problem with my assignments is that they're a bit too hypothetical for comfort. Here's what I have thus far:
C-NMR: peaks D, E & L (lowest intensity) are C5, C13 and C7 respectively. Of these three carbons, C7 was the furthest away from electronegative atoms N & O, and C5 was the closest. Peaks A and B have to be C1 and C3 respectively. Peaks G & H have the second lowest intensity, so I think these should be C16 and C10, though I'm uncertain which is which.
How am I doing so far? Making sense?
I've no idea why there is a solvent signal in the H-NMR because d6-DMSO, the solvent contains D instead of H atoms.
Looking at the HMQC (attached below), I see C5 and C13 producing no cross peaks, which corroborates the argument. C6, which I believe to be C-NMR peak C, has one cross-peak with H-NMR peak C, defining the C--H link at that position. The integral of the H-NMR peak supports this single-proton assignment.
edit: removed HMQC since it was already posted.