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Topic: Equilibrium constant- solving for concentrations when K(c) is large  (Read 2183 times)

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Offline vverityv

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Equilibrium constant- solving for concentrations when K(c) is large
« on: June 23, 2012, 07:22:36 PM »
Can anyone help me with this problem?  I know that when K(c) is either very large or very small you can approximate what x will be..

The equilibrium constant for the balanced reaction:

Br(2) + 4/3 O(3) ----> 2 BrO(2) K(c) = 2.18x10^8. Calculate equilibrium contrentation of Br when 3.0 moles of Br and 8.0 moles of O are reacted in a 1.0 liter flask.

I know the answer is 2.6x10^-8, but I can't seem to get that answer when I approximate that x<3.  I don't know what I'm doing wrong. Can anyone help?
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Offline Borek

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Re: Equilibrium constant- solving for concentrations when K(c) is large
« Reply #1 on: June 24, 2012, 04:46:15 AM »
Show precisely what you are doing, hard to tell with so general remarks.
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Offline vverityv

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Re: Equilibrium constant- solving for concentrations when K(c) is large
« Reply #2 on: June 28, 2012, 01:00:02 AM »
I'm sorry my internet's been down...

   I actually figured it out, I was having trouble shifting the equilibrium.  Thanks though!
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