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Topic: Question about activation energy  (Read 5201 times)

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Helpimstuck

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Question about activation energy
« on: December 06, 2005, 05:27:17 PM »
I know that when you increase a reaction at room temperature (25 degrees) by 10 degrees it doubles the reaction rate, but what activation energy is implied by this?

Offline Borek

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Re:Question about activation energy
« Reply #1 on: December 06, 2005, 06:18:07 PM »
Arrhenius equation.
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Re:Question about activation energy
« Reply #2 on: December 08, 2005, 07:24:17 PM »
K = Ae-Ea/RT
ln K = ln A - Ea/RT
Ea/RT = ln A - ln K = ln (A/K)
RT = Ea/ln(A/K)
Ea = RT.ln(A/K)

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