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Topic: Balancing skeleton reaction  (Read 16580 times)

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Offline qwertqwert

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Balancing skeleton reaction
« on: August 03, 2012, 04:43:59 PM »
The question:

Balance the following skeleton reactions and identify the oxidizing
and reducing agents:

O2(g) + NO(g) -> NO3- (aq) [acidic]

My question:

I understand which ones are the oxidizing and reducing agents, but I'm confused on how to balance this.

The answer is supposed to be: 3O2(g) + 4NO(g) + 2H2O(l) -> 4NO3-(aq) + 4H+


Here is what I've done (You can ignore this if you want) :

1.

NO -> NO3-

O2 -> 2H2O

2.

NO + 2H2O -> NO3-

O2 -> 2H2O

3.

NO + 2H2O -> NO3- + 4H+

O2 + 4H+ -> 2H2O

4.

NO + 2H2O -> NO3- + 4H+ 3e-

O2 + 4H+ + 2e- -> 2H2O

5. Finally, I balanced the electrons by multiplying each rxn, and I ended up with:


3O2 + 4H+ + 2NO --> 2H20 + 2NO3-


I'd really appreciate any input on this.

Thanks!


« Last Edit: August 03, 2012, 05:07:06 PM by qwertqwert »

Offline AWK

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Re: Balancing skeleton reaction
« Reply #1 on: August 03, 2012, 05:21:23 PM »
Quote
O2 + 4H+ + 2e- -> 2H2O
Wrong charge balance
AWK

Offline qwertqwert

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Re: Balancing skeleton reaction
« Reply #2 on: August 03, 2012, 05:28:29 PM »
Figured it out now lol

Thanks a lot!!

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