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Topic: Problem of the week - 17/09/2012  (Read 21144 times)

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Offline DrCMS

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Re: Problem of the week - 17/09/2012
« Reply #15 on: September 19, 2012, 04:45:20 AM »
I agree with Raderford carry on doing them please Borek.  I especially liked the middle one Raderfordd linked to as that involved a bit to completely solve it and is a more real world application of chemistry.  I'd like to see more questions like that that require a bit of thinking about and working out rather than just a google search to find a compound with the right mass/colour/other property etc.  but I enjoy trying to get the right answer to all these questions.

Offline Schrödinger

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Re: Problem of the week - 17/09/2012
« Reply #16 on: September 19, 2012, 05:38:55 AM »
Please do continue. I haven't active in this POTW section, but that's only because I lack chemical knowledge. I am still in the learning phase, getting to know stuff. For instance, I know nothing of several topics like electrochem, thermodynamics, acid-base titration, etc. It will take me atleast a year to master these concepts properly (atleast the basics). But reading this section and going through discussions has always been a pleasure
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Offline AWK

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Re: Problem of the week - 17/09/2012
« Reply #17 on: September 19, 2012, 06:31:34 AM »
Yeah, so don't we have 3 possibilities? Just consolidating : pent-2-ene, 2-methylbut-1-ene and 2-methylbut-2-ene.
Theoretically one more example is possible - bromination of CH2TF (T - tritium)
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Online Borek

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Re: Problem of the week - 17/09/2012
« Reply #18 on: September 19, 2012, 07:30:50 AM »
CH2TF (T - tritium)

That's not an olefin - olefin must be unsaturated.
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Offline fledarmus

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Re: Problem of the week - 17/09/2012
« Reply #19 on: September 19, 2012, 08:42:49 AM »
Yes, please continue the problems of the week! I rarely contribute an answer, but I enjoy the process of thinking through the problems and reading what other people come up with. The more-or-less real world applications are my favorites.

Online Borek

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Re: Problem of the week - 17/09/2012
« Reply #20 on: September 24, 2012, 08:07:14 AM »
I am going to try a problem with a chiral compound once again  :P

As mentioned earlier, there are more possible answers. Generally speaking there are probably infinitely many answers, as every compound with the formula (C5H10Br2)n will have the same bromine percentage.
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