[Yusuf]

MnO4‾(aq) + S2-(aq) → MnS(s) + S(s)



MnO4- ---> Mn2+
S2- ---> S

Why/How can someone remove the S from MnS?

[UG]

I am not sure what you mean, please elaborate.

[Yusuf]

I am not sure what you mean, please elaborate.

In the solution for the redox problem, the guy split up the equations in to two, but he also removed the S from the MN when he splited them up.

[UG]

In the solution for the redox problem, the guy split up the equations in to two, but he also removed the S from the MN when he splited them up.

This redox reaction is not balanced, so in order to balance it, you need to split the reaction into two half reactions, an oxidation half and a reduction half, that is what this guy has done. The reduction half equation is MnO₄^- ---> Mn²⁺ and the oxidation half equation is S^2- S. Then you balance these two half reactions individually.
Some of the (non oxidised) sulphur remains with Mn in MnS (where S is in the -2 oxidation state) and some of the sulphur exists as elemental sulphur, where is it in the 0 oxidation state.

[Yusuf]

In the solution for the redox problem, the guy split up the equations in to two, but he also removed the S from the MN when he splited them up.

This redox reaction is not balanced, so in order to balance it, you need to split the reaction into two half reactions, an oxidation half and a reduction half, that is what this guy has done. The reduction half equation is MnO₄^- ---> Mn²⁺ and the oxidation half equation is S^2- S. Then you balance these two half reactions individually.
Some of the (non oxidised) sulphur remains with Mn in MnS (where S is in the -2 oxidation state) and some of the sulphur exists as elemental sulphur, where is it in the 0 oxidation state.

MnO4- ---> Mn2+

So, what you are saying is that if something is not a oxidizing agent or a reducing agent then their is no need to include it in the 2 split up equations?

[Vidya]

MNO4- ---> Mn 2+
it is the reduction reaction and MNO4- is the oxidizing agent.Check how the oxidation number of Mn is changing from left to right.

[UG]

MnO4- ---> Mn2+

So, what you are saying is that if something is not a oxidizing agent or a reducing agent then their is no need to include it in the 2 split up equations?

Yes, most of the time it is not necessary to put in the counter ions which do not take part in the reactions.

[Yusuf]

MnO4- ---> Mn2+

So, what you are saying is that if something is not a oxidizing agent or a reducing agent then their is no need to include it in the 2 split up equations?

Yes, most of the time it is not necessary to put in the counter ions which do not take part in the reactions.

Thank you! Do you know of any Chemistry book that teaches Chemistry like this? Straight forward and understandable.

[Borek]

Every general chemistry book I have seen contained a chapter on net ionic equations.