[gurpalc]

My problem is in the attachment. I am trying to find the molarity and volume of Cu(NO3)2 while I only know Cu has .50 g and HNO3 is 10M and is 5mL. I have done my calculations on the right. What I have circled is what I believe to be the moles of Cu(NO3)2. The copper is limiting I assume. I don't know where to go from there. Please help.

MY PROBLEM IS IN THIS LINK

http://imgur.com/EIMXd

[sjb]

My problem is in the attachment. I am trying to find the molarity and volume of Cu(NO3)2 while I only know Cu has .50 g and HNO3 is 10M and is 5mL. I have done my calculations on the right. What I have circled is what I believe to be the moles of Cu(NO3)2. The copper is limiting I assume. I don't know where to go from there. Please help.

MY PROBLEM IS IN THIS LINK

http://imgur.com/EIMXd

Is this the same sample that you are using in part 2? What is the definition of concentration?

[Vidya]

2Cu + 4HNO3 ---->Cu(NO3)2 + 2H2O + NO2
moles of Cu = 7.87X10^-3 (this have done correct)
you are right that Cu is the limiting reactant

now you want to know molarity
so molarity = moles /volume
 you have moles of Cu(NO3)2 and volume is the same as the volume of the soln (5mL) .Do not forget to change volume in L Now you can plugin the vlaues to get the molarity.

molarity X volume  will give you moles of Cu2+ and then that can be converted into grams  of Cu .

[gurpalc]

2Cu + 4HNO3 ---->Cu(NO3)2 + 2H2O + NO2
moles of Cu = 7.87X10^-3 (this have done correct)
you are right that Cu is the limiting reactant

now you want to know molarity
so molarity = moles /volume
 you have moles of Cu(NO3)2 and volume is the same as the volume of the soln (5mL) .Do not forget to change volume in L Now you can plugin the vlaues to get the molarity.

molarity X volume  will give you moles of Cu2+ and then that can be converted into grams  of Cu .

My question is why would I use 5 mL as the volume of Cu(NO3)2. Wouldn't 5 grams of Cu(s) add to that and isn't that 5 mL in excess, so we can't use all of it?
Please answer.