Lets start from blue solution (CuSO4).
After mixing separate samples of this solution with sample of each other, only in two cases precipitate will be formed, namely with NaOH and with Na2CO3.
Prepare two samples from remainded three solutions (AgNO3, FeCl3 and HCl) and add to each sample NaOH or Na2CO3.
Only from sample Na2CO3 + HCl bubbles of CO2 will evolve indicating both HCl and Na2CO3.
White precipitate in one of other samples treated with Na2CO3 indicate AgNO3.
Brown precipitates with both NaOH and Na2CO3 indicate FeCl3